Mazda 5. Manual — part 26
05–17–24
AUTOMATIC TRANSAXLE
End Of Sie
PLANETARY GEAR STRUCTURE
B3E051701030A21
• The front planetary gear is integrated with the one-way clutch outer race and engaged with the drive plate of
the low and reverse brake.
Because of this, when the front planetary gear rotates, the one-way clutch outer race and the drive plate of the
low and reverse brake also rotate together.
• The front sun gear is installed inside of the front pinion gears, and the front internal gear is installed outside of
the front pinion gears. The front sun gear is engaged with the forward clutch hub, and the front internal gear is
engaged with the rear planetary carrier.
• The rear planetary gear and the rear pinion gear have the rear sun gear installed inside and the rear internal
gear outside. The rear sun gear is engaged with the turbine shaft via the 2-4 brake drum, and the rear internal
gear is engaged with the primary gear via the front planetary carrier.
.
End Of Sie
PLANETARY GEAR OPERATION
B3E051701030A22
• The planetary gear works as a transaxle when the sun gear and the internal gear are engaged.
• The sun gear, installed inside of the pinion gears, and the internal gear, installed outside of the pinion gears,
are engaged with their respective gears.
9
8
7
5
4
3
6
1
2
B3E0517A005
1
Rear internal gear
2
Front internal gear
3
Low and reverse brake
4
Rear planetary carrier
5
Rear pinion gear
6
Rear sun gear
7
Front pinion gear
8
Front planetary carrier
9
Front sun gear
AUTOMATIC TRANSAXLE
05–17–25
05
The sun gear and the internal gear rotate on the
center of the planetary gear.
.
• The pinion gears turn in the following two ways:
— On their own centers (rotation)
— On the center of the planetary gear
(revolution)
.
Gear ratio of each range
• The relation between each element of the planetary gear set and the rotation speed is generally indicated in
the formula below.
(Z
R
+Z
S
) N
C
=Z
R
N
R
+Z
S
N
S
: formula (1)
"
!
B3E0517A006
1
Sun gear
2
Internal gear
3
Planetary carrier
4
Pinion gear
1
2
B3E0517A007
1
Rotation
2
Revolution
05–17–26
AUTOMATIC TRANSAXLE
In this formula Z stands for the number of teeth, N
stands for the rotation speed, and R, S, C stand
for each gear element (refer to the table below).
.
Number of teeth and symbol of each gear
First gear
.
Gear rotation speed
• Suppose gear ratio in first gear is i
1
,
i
1
=N
S
/N
C
• From the result N
R
=0 in formula (1), the relation between the gear ratio in first gear and the rotation speed of
the planetary gear set is indicated in the formula below.
(Z
RF
+Z
SF
) N
C
=Z
SF
N
S
Therefore,
i
1
=N
S
/N
C
= (Z
RF
+Z
SF
) /Z
SF
= (89+49) /49=2.8163
"
!
B3E0517A006
1
Sun gear
2
Internal gear
3
Planetary carrier
4
Pinion gear
Planetary gear unit
Planetary gear
element
Number of teeth
Unit identification symbol
Gear element
Unit
Front
Internal gear
89
R
F
Planetary carrier
(part of pinion gear)
20
C
F
Sun gear
49
S
F
Rear
Internal gear
98
R
R
Planetary carrier
(part of pinion gear)
30
C
R
Sun gear
37
S
R
1
Front planetary gear
2
Sun gear N
S
(input)
3
Internal gear (fix)
4
Planetary carrier N
C
(output)
5
Pinion gear
Planetary gear unit
Front
Internal gear
0 (fix)
Planetary carrier
N
C
(output)
Sun gear
N
S
(input)
5
4
3
1
2
B3E0517A008
AUTOMATIC TRANSAXLE
05–17–27
05
As a result, the gear ratio in first gear is 2.816.
Second gear
Gear rotation speed
Note
• The front internal gear and the rear planetary carrier are integrated.
• The front planetary carrier and the rear internal gear rotate at the same speed.
• Suppose gear ratio in second gear is i
2
,
i
2
=N
S
/N
R
• From formula (1), the relation between the gear ratio in second gear and the rotation speeds of the front and
the rear planetary gar sets is indicated in formulas (2) and (3).
(Z
RF
+Z
SF
) N
R
=Z
RF
N
C
+Z
SF
N
S
: (2) (Front planetary gear set)
(Z
RR
+Z
SR
) N
C
=Z
RR
N
R
+Z
SR
N
S
: (3) (Rear planetary gear set)
• From the result N
S
=0 in formula (3).
N
C
= (Z
RR
/ (Z
RR
+Z
SR
)) N
R
: (4)
• Here we substitute formula (4) in formula (2).
Z
SR
N
S
= (((Z
RR
+Z
SR
) (Z
RF
+Z
SF
) –Z
RF
Z
RR
) / (Z
RR
+Z
SR
)) N
R
Therefore,
i
2
=N
S
/N
R
= (((Z
RR
+Z
SR
) (Z
RF
+Z
SF
) –Z
RF
Z
RR
) / (Z
SF
(Z
RR
+Z
SR
))) N
R
= ((98+37)(84+49) –8998) / (49 (98+37))
=1.4978
As a result, the gear ratio in second gear is 1.497.
1
9
8
5
4
3
6
2
6
7
B3E0517A009
1
Front planetary gear
2
Rear planetary gear
3
Sun gear N
S
(input)
4
Internal gear N
R
5
Planetary carrier N
C
(output)
6
Pinion gear
7
Sun gear N
S
(fix)
8
Internal gear N
R
(output)
9
Planetary carrier N
C
Planetary gear
Front
Rear
Internal gear
N
R
N
R
(output)
Planetary carrier
N
C
(output)
N
C
Sun gear
N
S
(input)
N
S
(fix)
Нет комментариевНе стесняйтесь поделиться с нами вашим ценным мнением.
Текст